Use of unsanitized data to open file

このページは日本語には対応しておりません。随時翻訳に取り組んでいます。翻訳に関してご質問やご意見ございましたら、お気軽にご連絡ください。

Metadata

ID: python-flask/open-file-unsanitized-data

Language: Python

Severity: Error

Category: Security

Description

Use of unsanitized from incoming request, leading to potential data leak and lack of control of the service. Do not use unsanitized data to control file operations. The code should check any incoming data and make sure it’s safe to use it.

Learn More

Non-Compliant Code Examples

import flask
import requests

app = flask.Flask(__name__)


@app.route("/route/to/resource/<resource_id>")
def resource1(resource_id):
    with open(resource_id) as f:
        pass
    with open(f"/path/to/{resource_id}") as f:
        pass
    with open("/path/to/{0}".format(resource_id)) as f:
        pass
    with open("/path/to/{0}".other(resource_id)) as f:
        pass

@app.route("/route/to/resource/<resource_id>")
def resource2(resource_id):
    file1 = open(resource_id)
    file2 = open(f"/path/to/{resource_id}")
    file3 = open("/path/to/{0}".format(resource_id))


@app.route("/route/to/resource")
def resource2():
    resource_id = flask.request.args.get("resource_id")
    file1 = open(resource_id)
    file2 = open(f"/path/to/{resource_id}")
    file3 = open("/path/to/{0}".format(resource_id))

Compliant Code Examples

import flask
import requests

app = flask.Flask(__name__)

@app.route("/route/to/resource/<resource_id>")
def resource2(resource_id):
    sanitized_resource_id = sanitize(resource_id)
    file1 = open(sanitized_resource_id)
https://static.datadoghq.com/static/images/logos/github_avatar.svg https://static.datadoghq.com/static/images/logos/vscode_avatar.svg jetbrains

Seamless integrations. Try Datadog Code Analysis